ScalingStacks

Proof. [01AA]

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Proof.

Pick φ0∈PSH⁡(X,θ)∩𝒟⁡(X)\varphi_{0}\in\PSH(X,\theta)\cap\mathcal{D}(X). Upon replacing θ\theta, φi\varphi_{i}, and ψ\psi with θ+d​dc​φ0\theta+dd^{c}\varphi_{0}, φi−φ0\varphi_{i}-\varphi_{0} and ψ−φ0\psi-\varphi_{0} respectively, we may assume that θ\theta is semipositive and that φi≤0\varphi_{i}\leq 0 for all ii. Adding a constant to ψ\psi we may also assume supXψ=0\sup_{X}\psi=0. Set M:=max⁡supi⁡|φi|M:=\max_{i}\sup|\varphi_{i}|. First assume that ψ\psi is also bounded. We claim that ∫−ψμ\int-\psi\mu is bounded by a constant depending only on MM (but not on supX|ψ|\sup_{X}|\psi|). Integrating by parts we have

0≤∫(−ψ)​μ=∫(−ψ)​θ∧(θ+d​dc​φ2)∧⋯∧(θ+d​dc​φn)+∫(−φ1)(θ+ddcψ)∧(θ+ddcφ2)∧⋯∧(θ+ddcφn)+∫φ1θ∧(θ+ddcφ2)∧⋯∧(θ+ddcφn).0\leq\int(-\psi)\mu=\int(-\psi)\theta\wedge(\theta+dd^{c}\varphi_{2})\wedge\dots\wedge(\theta+dd^{c}\varphi_{n})\\ +\int(-\varphi_{1})(\theta+dd^{c}\psi)\wedge(\theta+dd^{c}\varphi_{2})\wedge\dots\wedge(\theta+dd^{c}\varphi_{n})+\int\varphi_{1}\theta\wedge(\theta+dd^{c}\varphi_{2})\wedge\dots\wedge(\theta+dd^{c}\varphi_{n}).

Here the second to last integral is bounded by M​{θ}nM\{\theta\}^{n}, while the last integral to the right is non-positive since θ∧(θ+d​dc​φ2)∧⋯∧(θ+d​dc​φn)\theta\wedge(\theta+dd^{c}\varphi_{2})\wedge\dots\wedge(\theta+dd^{c}\varphi_{n}) is a positive measure. Hence

∫(−ψ)​μ≤∫(−ψ)​θ∧(θ+d​dc​φ2)∧⋯∧(θ+d​dc​φn)+M​{θ}n.\int(-\psi)\mu\leq\int(-\psi)\theta\wedge(\theta+dd^{c}\varphi_{2})\wedge\dots\wedge(\theta+dd^{c}\varphi_{n})+M\{\theta\}^{n}.

Iterating this argument yields

0≤∫(−ψ)​μ≤∫(−ψ)​θn+n​M​{θ}n.0\leq\int(-\psi)\mu\leq\int(-\psi)\theta^{n}+nM\{\theta\}^{n}.

Now ∫(−ψ)​θn\int(-\psi)\theta^{n} is bounded above by some C>0C>0 only depending on θ\theta, by compactness of {ψ∈PSH⁡(X,θ)∣supXψ=0}\{\psi\in\PSH(X,\theta)\mid\sup_{X}\psi=0\} and the fact that θn\theta^{n} is an atomic measure supported at finitely many divisorial points. We conclude that

(3.3) 0≤∫(−ψ)​μ≤C+n​M​{θ}n0\leq\int(-\psi)\mu\leq C+nM\{\theta\}^{n}

for some constant C>0C>0 only depending on θ\theta, as long as ψ\psi is a bounded θ\theta-psh function with supXψ=0\sup_{X}\psi=0. If ψ\psi is now a possibly unbounded θ\theta-psh function normalized by supXψ=0\sup_{X}\psi=0, ψ\psi is the decreasing limit of the bounded θ\theta-psh functions ψm:=max⁡{ψ,−m}\psi_{m}:=\max\{\psi,-m\}, so that (3.3) continues to hold, by monotone convergence. ∎

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