ScalingStacks

Proof. [033F]

Original official author HTML, exact retained edition. Historical TeX conversion verdicts remain unchanged. Cited-edition alignment and mathematical self-containment are not assessed.

Complete original source context · Original author HTML

Proof.

Assume supXVK,ω∗=+∞\sup_{X}V_{K,\omega}^{*}=+\infty. By a lemma of Choquet (see lemma 4.23 in [15], chapter 1), we can find an increasing sequence of functions φj∈P​S​H​(X,ω)\varphi_{j}\in PSH(X,\omega) such that φj=0\varphi_{j}=0 on KK and VK,ω∗=(lim↗φj)∗V_{K,\omega}^{*}=(\lim\nearrow\varphi_{j})^{*}. Extracting a subsequence if necessary, we can assume supXφj≥2j\sup_{X}\varphi_{j}\geq 2^{j}. Set ψj=φj−supXφj\psi_{j}=\varphi_{j}-\sup_{X}\varphi_{j}. These functions belong to ℱ0{\mathcal{F}}_{0} which is a compact subfamily of P​S​H​(X,ω)PSH(X,\omega) (corollary 1.7). Recall that if μ\mu is a smooth volume form on XX then there exists CμC_{\mu} such that ∫ψj​𝑑μ≥−Cμ\int\psi_{j}d\mu\geq-C_{\mu} for all jj. Set ψ:=∑j≥12−j​ψj\psi:=\sum_{j\geq 1}2^{-j}\psi_{j}. Then ψ∈P​S​H​(X,ω)\psi\in PSH(X,\omega) as a decreasing limit of functions in P​S​H​(X,ω)PSH(X,\omega) with ∫Xψ​𝑑μ≥−Cμ>−∞\int_{X}\psi d\mu\geq-C_{\mu}>-\infty. Now for every x∈Kx\in K we get ψ(x)=−∑j≥12−jsupXφj=−∞\psi(x)=-\sum_{j\geq 1}2^{-j}\sup_{X}\varphi_{j}=-\infty hence K⊂{ψ=−∞}K\subset\{\psi=-\infty\}, i.e. KK is P​S​H​(X,ω)PSH(X,\omega)-polar.

Conversely assume KK is P​S​H​(X,ω)PSH(X,\omega)-polar, K⊂{ψ=−∞}K\subset\{\psi=-\infty\} for some ψ∈P​S​H​(X,ω)\psi\in PSH(X,\omega). Then for all c∈ℝc\in\mathbb{R}, ψ+c∈P​S​H​(X,ω)\psi+c\in PSH(X,\omega) and ψ+c≤0\psi+c\leq 0 on KK. Therefore VK,ω≥ψ+cV_{K,\omega}\geq\psi+c, ∀c∈ℝ\forall c\in\mathbb{R}. This yields VK,ω=+∞V_{K,\omega}=+\infty on X∖{ψ=−∞}X\setminus\{\psi=-\infty\} hence VK,ω∗≡+∞V_{K,\omega}^{*}\equiv+\infty on XX since {ψ=−∞}\{\psi=-\infty\} has zero volume. We have thus shown the following circle of implications: K​ is ​P​S​H​(X,ω)−polar⇒VK,ω∗≡+∞⇒supXVK,ω∗=+∞⇒K​ is ​P​S​H​(X,ω)−polarK\text{ is }PSH(X,\omega)-\text{polar}\Rightarrow V_{K,\omega}^{*}\equiv+\infty\Rightarrow\sup_{X}V_{K,\omega}^{*}=+\infty\Rightarrow K\text{ is }PSH(X,\omega)-\text{polar}.

Assume now that KK is not P​S​H​(X,ω)PSH(X,\omega)-polar. Then VK,ω∗∈P​S​H​(X,ω)V_{K,\omega}^{*}\in PSH(X,\omega) (see proposition 1.6.2) and clearly satisfies VK,ω∗=0V_{K,\omega}^{*}=0 in the interior of K{K}. If we show that (ωVK,ω∗)n=0(\omega_{V_{K,\omega}^{*}})^{n}=0 in X∖K¯X\setminus\overline{K} then

∫K¯(ωVK,ω∗)n=∫X(ωVK,ω∗)n=∫Xωn,\int_{\overline{K}}(\omega_{V_{K,\omega}^{*}})^{n}=\int_{X}(\omega_{V_{K,\omega}^{*}})^{n}=\int_{X}\omega^{n},

as follows from Stokes theorem. Let φj∈P​S​H​(X,ω)\varphi_{j}\in PSH(X,\omega) be an increasing sequence such that φj=0\varphi_{j}=0 on KK and VK,ω∗=(lim↗φj)∗V_{K,\omega}^{*}=(\lim\nearrow\varphi_{j})^{*}. Fix BB a small ball in X∖K¯X\setminus\overline{K}. Let φj^\hat{\varphi_{j}} be the solution of the Dirichlet problem with boundary values φj\varphi_{j}. Then φj^∈P​S​H​(X,ω)\hat{\varphi_{j}}\in PSH(X,\omega), φj^=φj\hat{\varphi_{j}}=\varphi_{j} in X∖BX\setminus B (in particular φj^=0\hat{\varphi_{j}}=0 on KK hence φj^≤VK,ω\hat{\varphi_{j}}\leq V_{K,\omega}) and the sequence (φj^)(\hat{\varphi_{j}}) is again increasing (theorem 2.12). Since (ωφj^)n=0(\omega_{\hat{\varphi_{j}}})^{n}=0 in BB and (lim↗φj^)=VK,ω∗(\lim\nearrow\hat{\varphi_{j}})=V_{K,\omega}^{*}, it follows from the continuity of the complex Monge-Ampère on increasing sequences that (ωVK,ω∗)n=0(\omega_{V_{K,\omega}^{*}})^{n}=0 in BB. As BB was an arbitrarily small ball in X∖K¯X\setminus\overline{K} we infer (ωVK,ω∗)n=0(\omega_{V_{K,\omega}^{*}})^{n}=0 in X∖K¯X\setminus\overline{K}. ∎

Original mathematics by the credited authors. Source-backed reader collection; mathematical self-containment is not assessed.