ScalingStacks

Example 3.15 . [03P5]

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Example 3.15.

Let (M,J,g,Ω)(M,J,g,\Omega) be a Calabi–Yau mm-fold, and (L1,E1),(L2,E2)(L_{1},E_{1}),(L_{2},E_{2}) be embedded, transversely-intersecting, special Lagrangian branes in MM with phases ei​π​ϕ1,ei​π​ϕ2e^{i\pi\phi_{1}},e^{i\pi\phi_{2}} for ϕ1<ϕ2\phi_{1}<\phi_{2}, with H​F∗HF^{*} unobstructed. Choose bounding cochains b1,b2b_{1},b_{2} for (L1,E1),(L2,E2)(L_{1},E_{1}),(L_{2},E_{2}). Let ≠β∈H​F1​((L2,E2,b2),(L1,E1,b1))0\!\neq\!\beta\!\in\!HF^{1}\bigl((L_{2},E_{2},b_{2}),(L_{1},E_{1},b_{1})\bigr), and (βp)∈C​F1​((L2,E2),(L1,E1))(\beta_{p})\in CF^{1}\bigl((L_{2},E_{2}),(L_{1},E_{1})\bigr) represent β\beta, where for all p∈L1∩L2p\in L_{1}\cap L_{2} with μL2,L1​(p)=1\mu_{L_{2},L_{1}}(p)=1 we have βp∈Hom𝔽(E2|p,E1|p)⊗𝔽Λnov\beta_{p}\in\mathop{\rm Hom}\nolimits_{\mathbin{\mathbb{F}}}\bigl(E_{2}|_{p},E_{1}|_{p}\bigr)\otimes_{\mathbin{\mathbb{F}}}\Lambda_{\rm nov} .

Suppose βp∈Hom𝔽(E2|p,E1|p)⊗𝔽Λnov⩾0\beta_{p}\in\mathop{\rm Hom}\nolimits_{\mathbin{\mathbb{F}}}\bigl(E_{2}|_{p},E_{1}|_{p}\bigr)\otimes_{\mathbin{\mathbb{F}}}\Lambda_{\rm nov}^{\geqslant 0} for all pp. Set (L,E)=(L1,E1)∪(L2,E2)(L,E)=(L_{1},E_{1})\cup(L_{2},E_{2}), considered as an immersed Lagrangian brane in MM. Then using the notation of §2.6, b=b1⊕b2⊕(βp)b=b_{1}\oplus b_{2}\oplus(\beta_{p}) is a bounding cochain for (L,E)(L,E), where bch=b1⊕b2b_{\rm ch}=b_{1}\oplus b_{2} in Cm−1​(L,Λnov+)=Cm−1​(L1,Λnov+)⊕Cm−1​(L2,Λnov+)C_{m-1}(L,\Lambda_{\rm nov}^{+})=C_{m-1}(L_{1},\Lambda_{\rm nov}^{+})\oplus C_{m-1}(L_{2},\Lambda_{\rm nov}^{+}), and the data bpb_{p} for each p∈Mp\in M at which two local sheets L+,L−L_{+},L_{-} of LL intersect transversely with μL+,L−​(p)=1\mu_{L_{+},L_{-}}(p)=1 are bp=βpb_{p}=\beta_{p} if L+=L2L_{+}=L_{2}, L−=L1L_{-}=L_{1}, and bp=0b_{p}=0 otherwise. We now have a distinguished triangle in the derived Fukaya category Dbℱ(M)D^{b}{\mathbin{\mathscr{F}}}(M) of immersed Lagrangians

(L1,E1,b1)\textstyle{(L_{1},E_{1},b_{1})\ignorespaces\ignorespaces\ignorespaces\ignorespaces}(L,E,b)\textstyle{(L,E,b)\ignorespaces\ignorespaces\ignorespaces\ignorespaces}(L2,E2,b2)\textstyle{(L_{2},E_{2},b_{2})\ignorespaces\ignorespaces\ignorespaces\ignorespaces}β\scriptstyle{\beta}(L1,E1,b1)​[1].\textstyle{(L_{1},E_{1},b_{1})[1].} (3.9)

Let us apply the programme of §3.2 to (L,E,b)(L,E,b). Since LL is a union of special Lagrangians of different phases, it is stationary under immersed Lagrangian MCF, so the obvious answer is that (Lt,Et,bt)=(L,E,b)(L^{t},E^{t},b^{t})=(L,E,b) for all t∈[0,∞)t\in[0,\infty). Equation (3.9) gives a diagram for (L,E,b)(L,E,b) of the form (3.4) with n=2n=2

0=F0\textstyle{0=F_{0}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}F1=(L1,E1,b1)\textstyle{F_{1}=(L_{1},E_{1},b_{1})\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}F2=(L,E,b).\textstyle{F_{2}=(L,E,b).\ignorespaces\ignorespaces\ignorespaces\ignorespaces}(L1,E1,b1)\textstyle{(L_{1},E_{1},b_{1})\ignorespaces\ignorespaces\ignorespaces\ignorespaces}[1]\scriptstyle{[1]}(L2,E2,b2)\textstyle{(L_{2},E_{2},b_{2})\ignorespaces\ignorespaces\ignorespaces\ignorespaces}[1]\scriptstyle{[1]}β\scriptstyle{\beta}

However, in §3.2 we want such a diagram with ϕ1>ϕ2\phi_{1}>\phi_{2}, but we assume that ϕ1<ϕ2\phi_{1}<\phi_{2}. So writing (Lt,Et,bt)=(L,E,b)(L^{t},E^{t},b^{t})=(L,E,b) for all t∈[0,∞)t\in[0,\infty) does not satisfy the programme of §3.2, as although we have long-time existence of Lagrangian MCF, the limiting behaviour at infinity is wrong, and this looks like a counterexample.

Here is the explanation. Although (at least initially) the Lt,EtL^{t},E^{t} are independent of tt, the bounding cochains btb^{t} do evolve in time. Suppose p∈L1∩L2p\in L_{1}\cap L_{2} with μL2,L1​(p)=1\mu_{L_{2},L_{1}}(p)=1. Then (2.18)–(2.21) with HLj=−θLj=−π​ϕjH_{L_{j}}=-\theta_{L_{j}}=-\pi\phi_{j} for j=1,2j=1,2 shows that the data bptb_{p}^{t} in btb^{t} should evolve according to the equation

dd​t​bpt=π⁡(ϕ1−ϕ2)⋅log⁡P⋅bpt,\frac{{\rm d}}{{\rm d}t}b_{p}^{t}=\pi(\phi_{1}-\phi_{2})\cdot\log P\cdot b_{p}^{t},

so as bp0=βpb_{p}^{0}=\beta_{p}, the solution is bpt=Pπ⁡(ϕ1−ϕ2)​t⋅βpb_{p}^{t}=P^{\pi(\phi_{1}-\phi_{2})t}\cdot\beta_{p}. Thus, we have

(Lt,Et)=(L1,E1)∐(L2,E2),bt=b1⊕b2⊕(Pπ⁡(ϕ1−ϕ2)​t⋅βp),(L^{t},E^{t})=(L_{1},E_{1})\amalg(L_{2},E_{2}),\quad b^{t}=b_{1}\oplus b_{2}\oplus(P^{\pi(\phi_{1}-\phi_{2})t}\cdot\beta_{p}), (3.10)

at least for small tt. Write βp=ap​Pλp+⋯\beta_{p}=a_{p}P^{\lambda_{p}}+\cdots if βp≠0\beta_{p}\neq 0, where 0≠ap∈Hom𝔽(E2|p,E1|p)0\neq a_{p}\in\mathop{\rm Hom}\nolimits_{\mathbin{\mathbb{F}}}\bigl(E_{2}|_{p},E_{1}|_{p}\bigr) and λp⩾0\lambda_{p}\geqslant 0, and set λp=∞\lambda_{p}=\infty if βp=0\beta_{p}=0. Then bpt=ap​Pλp+π⁡(ϕ1−ϕ2)​t+⋯b_{p}^{t}=a_{p}P^{\lambda_{p}+\pi(\phi_{1}-\phi_{2})t}+\cdots, so bpt∈Hom𝔽(E2t|p,E1t|p)⊗𝔽Λnov⩾0b_{p}^{t}\in\mathop{\rm Hom}\nolimits_{\mathbin{\mathbb{F}}}\bigl(E_{2}^{t}|_{p},E_{1}^{t}|_{p}\bigr)\otimes_{\mathbin{\mathbb{F}}}\Lambda_{\rm nov}^{\geqslant 0} if t∈[0,λp/π⁡(ϕ2−ϕ1)]t\in[0,\lambda_{p}/\pi(\phi_{2}-\phi_{1})].

Thus, at time T=(minp⁡λp)/π⁡(ϕ2−ϕ1)T=(\min_{p}\lambda_{p})/\pi(\phi_{2}-\phi_{1}), the flow crosses a ‘wall’ after which btb^{t} in (3.10) is no longer a bounding cochain, as bptb_{p}^{t} leaves Hom𝔽(E2t|p,E1t|p)⊗𝔽Λnov⩾0\mathop{\rm Hom}\nolimits_{\mathbin{\mathbb{F}}}\bigl(E_{2}^{t}|_{p},E_{1}^{t}|_{p}\bigr)\otimes_{\mathbin{\mathbb{F}}}\Lambda_{\rm nov}^{\geqslant 0} for some pp. We claim that the right thing to do is to ‘open a neck’ at time t=Tt=T at each pp with λp\lambda_{p} minimal, gluing in a Joyce–Lee–Tsui LMCF expander. Then Lt,EtL^{t},E^{t} will undergo some nontrivial evolution for t>Tt>T.

To see that a suitable LMCF expander exists to glue in at pp, note that θLj​(p)=π​ϕj\theta_{L_{j}}(p)=\pi\phi_{j} for j=1,2j=1,2, so θL1​(p)<θL2​(p)\theta_{L_{1}}(p)<\theta_{L_{2}}(p) by assumption, and as μL2,L1​(p)=1\mu_{L_{2},L_{1}}(p)=1, the first equation of (2.13) gives θL2​(p)<θL1​(p)+π\theta_{L_{2}}(p)<\theta_{L_{1}}(p)+\pi. These are the conditions for the existence of an LMCF expander in Tp​MT_{p}M asymptotic to Tp​L1∪Tp​L2T_{p}L_{1}\cup T_{p}L_{2}.

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