Proof. [03BV]
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Proof.
The proof follows mainly the arguments in [GK15, Proposition 6.4]. By Lemma 3.3 and Lemma 3.4, we may assume that is algebraically closed and that is reduced. Let be a formal -model of with . We assume that is semipositive in every . We choose a closed curve in which is proper over . We have to show that . By surjectivity of the reduction map , there is such that is the generic point of . Since is semipositive in , there is a compact strictly -affinoid neighborhood of and a nef formal -model of such that over . Using Proposition 3.5, we may always replace the models and by dominating formal -models and the line bundles and by their pull-backs. By [BL93b, Corollary 5.4], we may therefore assume that is a formal open subset of . Then is also a formal -model of and hence Proposition 3.5 shows that is nef.
Since is a neighbourhood of and since is boundaryless, we conclude that the boundary of is the topological boundary of in (see [Ber90, Corollary 2.5.13(ii), Proposition 3.1.3(ii)]). In particular, is no boundary point of as is a neighborhood of . Using [CD12, Lemma 6.5.1], such interior points are characterized by the property that the closure of the reduction in is proper over . We conclude that the closure of in is equal to . Since is nef, it follows that . ∎