ScalingStacks

Remark 4.2 . [0396]

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Remark 4.2.
  1. (i)

    Observe that we have τ⁡(𝔞λ)=(𝔞⌈λ​pe⌉)[1/pe]\tau({\mathfrak{a}}^{\lambda})=({\mathfrak{a}}^{\lceil\lambda p^{e}\rceil})^{[1/p^{e}]} for large e∈ℕe\in\mathbb{N} as XX is noetherian. The equality

    (4.4) τ⁡((𝔞m)λ)=τ⁡(𝔞λ​m)\tau(({\mathfrak{a}}^{m})^{\lambda})=\tau({\mathfrak{a}}^{\lambda m})

    for m∈ℕm\in\mathbb{N} shows that the notation in Definition 4.1 is compatible with taking powers of ideals [BMS08, Cor. 2.15]. We have τ⁡(𝔞λ)⊆τ⁡(𝔟λ)\tau({\mathfrak{a}}^{\lambda})\subseteq\tau({\mathfrak{b}}^{\lambda}) for ideals 𝔞⊆𝔟{\mathfrak{a}}\subseteq{\mathfrak{b}} in 𝒪X{\mathcal{O}}_{X} [BMS08, Prop. 2.11(i)].

  2. (ii)

    Choose ee such that τ⁡(𝔞)=(𝔞[pe])[1/pe]\tau({\mathfrak{a}})=({\mathfrak{a}}^{[p^{e}]})^{[1/p^{e}]}. For any ideal 𝔟{\mathfrak{b}} in 𝒪X{\mathcal{O}}_{X} such that 𝔞[pe]⊆𝔟[pe]{\mathfrak{a}}^{[p^{e}]}\subseteq{\mathfrak{b}}^{[p^{e}]} we get 𝔞⊆𝔟{\mathfrak{a}}\subseteq{\mathfrak{b}} from (4.1). Hence (4.3) implies

    (4.5) 𝔞⊆τ⁡(𝔞).{\mathfrak{a}}\subseteq\tau({\mathfrak{a}}).

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