Proof.
Let . We can assume w.l.o.g. that on .
Let
denote the associated (singular)
positive metric of on , where denotes an open
cover of trivializing (see section 4).
Step 1. We consider the following Bergman spaces
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where , a fixed large integer
(to be specified later). Let
be an orthonormal basis
of and set
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where denotes the unit ball of radius 1 centered at 0 in
. Clearly defines a positive (singular)
metric of on , equivalently .
If and ,
then is subharmonic in hence
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where is so small that .
We infer
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There is also a reverse inequality which uses a deep extension
result of Ohsawa-Takegoshi-Manivel (see [14]): there exists
and large enough so that
, there exists
with
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Choose so that the right hand side is equal to ,
hence . Then
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We infer
| (4) |
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since on . It follows from (3) and (4) that
in .
Step 2.
We now show, following [16] that is almost subadditive.
Let with
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We may view as the restriction to the diagonal of
of a section ,
where and denotes the projection
onto the factor, .
Consider the Bergman spaces
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where . It follows from the Ohsawa-Takegoshi-Manivel
-extension theorem [15] that there exists
such that
and
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where only depends on the dimension .
Observe that
forms an orthonormal basis of , thus
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with
. It follows therefore from Cauchy-Schwarz
inequality that
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which yields
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Note finally that since ,
therefore is decreasing.
Step3. It remains to make smooth. Indeed it has all the
other required properties: it is decreasing and by Step 1 we have for all
,
| (5) |
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so that .
Let be such that is a basis
of and set
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Clearly . Moreover
because is very ample if is large enough (hence we can find,
for every , a holomorphic section of on
which does not vanish at ). Finally we can choose that decrease
so fast to zero that is still decreasing and converges to .
∎