ScalingStacks

Theorem 1.10 [014A]

Original official author HTML, exact retained edition. Historical TeX conversion verdicts remain unchanged. Cited-edition alignment and mathematical self-containment are not assessed.

Complete original source context · Original author HTML

Theorem 1.10

Let f:X→Bf:X\rightarrow B be a well-behaved T3T^{3}-fibration, and let b0∈Δb_{0}\in\Delta with Xb0X_{b_{0}} be a semistable fibre with monodromy group GG. Then either

(1) Xb0X_{b_{0}} is of type (2,2)(2,2) and GG is conjugate to

{(10a010001)|a∈𝐙}.\left\{\pmatrix{1&0&a\cr 0&1&0\cr 0&0&1\cr}\bigg|a\in{\bf Z}\right\}.

(2) Xb0X_{b_{0}} is of type (2,1)(2,1) and GG is conjugate to

{(1ab010001)|a,b∈𝐙}.\left\{\pmatrix{1&a&b\cr 0&1&0\cr 0&0&1\cr}\bigg|a,b\in{\bf Z}\right\}.

(3) Xb0X_{b_{0}} is of type (1,2)(1,2) and GG is conjugate to

{(10a01b001)|a,b∈𝐙}.\left\{\pmatrix{1&0&a\cr 0&1&b\cr 0&0&1\cr}\bigg|a,b\in{\bf Z}\right\}.

(4) Xb0X_{b_{0}} is of type (1,1)(1,1) and GG is conjugate to

{(1ab01c001)|a,b,c∈𝐙}.\left\{\pmatrix{1&a&b\cr 0&1&c\cr 0&0&1\cr}\bigg|a,b,c\in{\bf Z}\right\}.

Original mathematics by the credited authors. Source-backed reader collection; mathematical self-containment is not assessed.