ScalingStacks

Verified tagged author-source HTML · 0905.4718v1 · cited publication edition alignment unverified.

Proof. Differentiating (4.3) we see that

Ric⁡(ω)=Ric⁡(ωY)−−1​∂∂¯​log⁡F.\mathrm{Ric}(\omega)=\mathrm{Ric}(\omega_{Y})-\sqrt{-1}\partial\overline{\partial}\log F.

If we fix y∈Y\f⁡(S)y\in Y\backslash f(S) and choose Ψ\Psi a local never vanishing holomorphic section of f∗​(ΩX/Yn−m)⊗kf_{*}(\Omega^{n-m}_{X/Y})^{\otimes k}, then we can define a local function u=(Ψ∧Ψ¯)1/kωS​Fn−mu=\frac{(\Psi\wedge\overline{\Psi})^{1/k}}{\omega_{SF}^{n-m}} on X\SX\backslash S, which is constant on each fiber XyX_{y}. Since ∫XyωS​Fn−m=1\int_{X_{y}}\omega_{SF}^{n-m}=1, we see that

−−1∂∂¯logu=ωW​P.-\sqrt{-1}\partial\overline{\partial}\log u=\omega_{WP}.

Then

(4.5) Ric⁡(ω)=Ric⁡(ωY)−−1​∂∂¯​log⁡u​Ω(Ψ∧Ψ¯)1k∧ω0m.\mathrm{Ric}(\omega)=\mathrm{Ric}(\omega_{Y})-\sqrt{-1}\partial\overline{\partial}\log\frac{u\Omega}{(\Psi\wedge\overline{\Psi})^{\frac{1}{k}}\wedge\omega_{0}^{m}}.

Picking local coordinates ziz^{i} as above, and writing

Ψ=K​[(−1)n−m​d​z1∧⋯∧d​zn−m]⊗k,\Psi=K[(\sqrt{-1})^{n-m}dz^{1}\wedge\dots\wedge dz^{n-m}]^{\otimes k},
ω0=−1​∑i,j=n−m+1ngi​j¯0​d​zi∧d​z¯j,\omega_{0}=\sqrt{-1}\sum_{i,j=n-m+1}^{n}g^{0}_{i\overline{j}}dz^{i}\wedge d\overline{z}^{j},
Ω=G​(−1)n​d​z1∧⋯∧d​z¯n,\Omega=G(\sqrt{-1})^{n}dz^{1}\wedge\dots\wedge d\overline{z}^{n},

we see that

u​Ω(Ψ∧Ψ¯)1k∧ω0m=u​G|K|2k​det(gi​j¯0),\frac{u\Omega}{(\Psi\wedge\overline{\Psi})^{\frac{1}{k}}\wedge\omega_{0}^{m}}=\frac{uG}{|K|^{\frac{2}{k}}\det(g^{0}_{i\overline{j}})},

and since KK is holomorphic and Ω\Omega is Ricci-flat we see that

−−1∂∂¯logu​G|K|2k​det(gi​j¯0)=ωW​P−Ric(ωY),-\sqrt{-1}\partial\overline{\partial}\log\frac{uG}{|K|^{\frac{2}{k}}\det(g^{0}_{i\overline{j}})}=\omega_{WP}-\mathrm{Ric}(\omega_{Y}),

which together with (4.5) gives (4.4). ∎

Original mathematics by the credited authors. Source collection and HTML conversion remain in progress.