ScalingStacks

Proof. [04SV]

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Proof.

We construct QnQ^{n} inductively by dimension nn. If n=0n=0 then H∘H^{\circ} is a point and Q0=H∘Q^{0}=H^{\circ}. Assume that QkQ^{k}, k<nk<n is already constructed. Consider the simplex

Δn(R)={x∈ℝn+1|−xj≤R,∑jxj≤R}.\Delta_{n}(R)=\{x\in\mathbb{R}^{n+1}\ |\ -x_{j}\leq R,\sum\limits_{j}x_{j}\leq R\}.

Each its kk-dimensional face is dual to a (n+1−k)(n+1-k)-cell of Σn\Sigma_{n}. Fix a sufficiently large number Rn>0R_{n}>0.

First we define Qn∩Log−1⁡(∂Δ⁡(Rn))Q^{n}\cap\operatorname{Log}^{-1}(\partial\Delta(R_{n})). Each kk-face of Δ⁡(Rn)\Delta(R_{n}) is contained in a unique affine kk-space AA in ℝn+1\mathbb{R}^{n+1}. Furthermore, the adjoint faces cut the polyhedron Δk−1​(Rn)⊂A\Delta_{k-1}(R_{n})\subset A. Thus we may identify AA with ℝk\mathbb{R}^{k} and, therefore, Log−1⁡(A)\operatorname{Log}^{-1}(A) with (ℂ∗)k(\mathbb{C}^{*})^{k}. By the induction assumption we already have Qk−1⊂(ℂ∗)k→ℝkQ^{k-1}\subset(\mathbb{C}^{*})^{k}\to\mathbb{R}^{k}. We define Qn∩Log−1⁡(∂Δ⁡(Rn))Q^{n}\cap\operatorname{Log}^{-1}(\partial\Delta(R_{n})) to be equal to the union of these QkQ^{k} for all faces of ∂Δ⁡(Rn)\partial\Delta(R_{n}). By the induction hypothesis (and since RnR_{n} was large enough) the choices over different faces agree.

Our next step is to extend QnQ^{n} to the complement of Log−1⁡(Δ⁡(Rn))\operatorname{Log}^{-1}(\Delta(R_{n})). For each face Δ′\Delta^{\prime} of ∂Δ⁡(Rn)\partial\Delta(R_{n}) consider its outer normal cone CΔ′⊂ℝn+1C_{\Delta^{\prime}}\subset\mathbb{R}^{n+1} (e.g. if Δ′\Delta^{\prime} is a facet then CΔ′C_{\Delta^{\prime}} is a ray). We define

Qn∩Log−1(Δ′+CΔ′)=⋃v→∈CΔ′ev→Qn∩Log−1(Δ′).Q^{n}\cap\operatorname{Log}^{-1}(\Delta^{\prime}+C_{\Delta^{\prime}})=\bigcup\limits_{\stackrel{{\scriptstyle\to}}{{v}}\in C_{\Delta^{\prime}}}e^{\stackrel{{\scriptstyle\to}}{{v}}}Q^{n}\cap\operatorname{Log}^{-1}(\Delta^{\prime}).

In other words, we span the region above the normal cone of a kk-face Δ′\Delta^{\prime} by the translates of the manifold QkQ^{k}.

We set Qn∩Log−1⁡(Δ⁡(Rn−1))=H∘∩Log−1⁡(Δ⁡(Rn−1))Q^{n}\cap\operatorname{Log}^{-1}(\Delta(R_{n}-1))=H^{\circ}\cap\operatorname{Log}^{-1}(\Delta(R_{n}-1)). By now we have defined QnQ^{n} everywhere, but Log−1⁡(Δ⁡(Rn)∖Δ⁡(Rn−1))\operatorname{Log}^{-1}(\Delta(R_{n})\smallsetminus\Delta(R_{n}-1)).

Consider a facet Δ′\Delta^{\prime} of ∂Δ⁡(Rn−1)\partial\Delta(R_{n}-1), e.g. the one sitting in the hyperplane A={xn+1=Rn−1}A=\{x_{n+1}=R_{n}-1\}. Since RnR_{n} is large enough, zn+1Rn−1z_{n+1}^{R_{n}-1} is small enough and the intersection H∘∩Log−1⁡(A)H^{\circ}\cap\operatorname{Log}^{-1}(A) is close enough to the zero set of z1+⋯+zn+1=0z_{1}+\dots+z_{n}+1=0. By the induction hypothesis this zero set can be deformed to Qn−1Q^{n-1}. We define Qn∩{Log|zn+1|=t}Q^{n}\cap\{\operatorname{Log}|z_{n+1}|=t\}, −Rn≤t≤−Rn+1-R_{n}\leq t\leq-R_{n}+1 using this deformation. We repeat the same procedure for all other facets of Δ⁡(Rn−1)\Delta(R_{n}-1). ∎

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