ScalingStacks

Verified tagged author-source HTML · 0905.4718v1 · cited publication edition alignment unverified.

We then fix η\eta a smooth function with support contained in KK, and we will also denote by η\eta its pullback to XX via ff. Recall that we have called ω~1\tilde{\omega}_{1} the Ricci-flat metric in the class [ω1][\omega_{1}], and Ω=ω~1n\Omega=\tilde{\omega}_{1}^{n}. Then from the Monge-Ampère equation (2.5) we have

(4.6) ∫Xη​Ω=1at​∫Xη​(ω0+t​ωX+−1​∂∂¯​φt)n,\int_{X}\eta\Omega=\frac{1}{a_{t}}\int_{X}\eta(\omega_{0}+t\omega_{X}+\sqrt{-1}\partial\overline{\partial}\varphi_{t})^{n},

where the constants ata_{t} are equal to

∫Xωtn∫Xω1n,\frac{\int_{X}\omega_{t}^{n}}{\int_{X}\omega_{1}^{n}},

and behave like (2.6). We can also write

(4.7) ∫Xη​Ω=∫Xη​F​ωS​Fn−m∧ω0m.\int_{X}\eta\Omega=\int_{X}\eta F\omega_{SF}^{n-m}\wedge\omega_{0}^{m}.

We are now going to estimate 1at​∫Xη​(ω0+t​ωX+−1​∂∂¯​φt)n.\frac{1}{a_{t}}\int_{X}\eta(\omega_{0}+t\omega_{X}+\sqrt{-1}\partial\overline{\partial}\varphi_{t})^{n}. We have

1at​∫Xη​(ω0+t​ωX+−1​∂∂¯​φt)n=1at​∫Xη⁡((ω0+−1​∂∂¯​φt¯)+(t​ωX+−1​∂∂¯​(φt−φt¯))nCLOSE=1at​∫Xη​∑k=0n(nk)​(ω0+−1​∂∂¯​φt¯)k∧(t​ωX+−1​∂∂¯​(φt−φt¯))n−k\begin{split}&\frac{1}{a_{t}}\int_{X}\eta(\omega_{0}+t\omega_{X}+\sqrt{-1}\partial\overline{\partial}\varphi_{t})^{n}\\ &=\frac{1}{a_{t}}\int_{X}\eta\left((\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}})+(t\omega_{X}+\sqrt{-1}\partial\overline{\partial}(\varphi_{t}-\underline{\varphi_{t}})\right)^{n}\\ &=\frac{1}{a_{t}}\int_{X}\eta\sum_{k=0}^{n}\binom{n}{k}(\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}})^{k}\wedge(t\omega_{X}+\sqrt{-1}\partial\overline{\partial}(\varphi_{t}-\underline{\varphi_{t}}))^{n-k}\end{split}

First of all observe that the form ω0+−1​∂∂¯​φt¯\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}} is the pullback of a form on YY, and it can be wedged with itself at most mm times, so all terms in the sum with k>mk>m are zero. Next, we claim that all the terms with k<mk<m go to zero as t→0t\to 0. To see this, start by observing that on the compact set KK the estimate (3.29) gives a constant CC (that depends on KK) such that

(4.8) −C​ωX≤−1​∂∂¯​φt≤C​ωX.-C\omega_{X}\leq\sqrt{-1}\partial\overline{\partial}\varphi_{t}\leq C\omega_{X}.

Moreover from the equation

∂∂¯​φt¯=f∗​(∂∂¯​φt∧ωXn−m)\partial\overline{\partial}\underline{\varphi_{t}}=f_{*}(\partial\overline{\partial}\varphi_{t}\wedge\omega_{X}^{n-m})

together with (4.8), (3.12), we see that on f⁡(K)f(K) we have

(4.9) −C​ωY≤−1​∂∂¯​φt¯≤C​ωY.-C\omega_{Y}\leq\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}}\leq C\omega_{Y}.

We also need to use (3.9) which on KK gives

(4.10) supK|φt−φt¯|≤C​t.\sup_{K}|\varphi_{t}-\underline{\varphi_{t}}|\leq Ct.

Then any term with k<mk<m is equal to

(nk)at​∫Xη​(ω0+−1​∂∂¯​φt¯)k∧(t​ωX+−1​∂∂¯​(φt−φt¯))n−k,\frac{\binom{n}{k}}{a_{t}}\int_{X}\eta(\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}})^{k}\wedge(t\omega_{X}+\sqrt{-1}\partial\overline{\partial}(\varphi_{t}-\underline{\varphi_{t}}))^{n-k},

and it can be expanded into

(nk)at​∑i=0n−k(n−ki)​∫Xη​(ω0+−1​∂∂¯​φt¯)k∧(t​ωX)n−k−i∧(−1​∂∂¯​(φt−φt¯))i.\frac{\binom{n}{k}}{a_{t}}\sum_{i=0}^{n-k}\binom{n-k}{i}\int_{X}\eta(\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}})^{k}\wedge(t\omega_{X})^{n-k-i}\wedge(\sqrt{-1}\partial\overline{\partial}(\varphi_{t}-\underline{\varphi_{t}}))^{i}.

On KK the (1,1)(1,1)-form ω0+−1​∂∂¯​φt¯\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}} is bounded by (4.9). Since at=O⁡(tn−m)a_{t}=O(t^{n-m}) from (2.6), we see that the term in this sum with i=0i=0 goes to zero. Any term with i>0i>0 is comparable to

(4.11) 1tn−m​∫X(φt−φt¯)​−1​∂∂¯​η∧(ω0+−1​∂∂¯​φt¯)k∧(t​ωX)n−k−i∧(−1​∂∂¯​(φt−φt¯))i−1.\frac{1}{t^{n-m}}\int_{X}(\varphi_{t}-\underline{\varphi_{t}})\sqrt{-1}\partial\overline{\partial}\eta\wedge(\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}})^{k}\wedge(t\omega_{X})^{n-k-i}\wedge(\sqrt{-1}\partial\overline{\partial}(\varphi_{t}-\underline{\varphi_{t}}))^{i-1}.

Notice that all the (1,1)(1,1)-forms appearing inside the integral are bounded by (4.8), (4.9), and that the function φt−φt¯\varphi_{t}-\underline{\varphi_{t}} is O⁡(t)O(t) by (4.10). On KK the estimate (2.10) gives

(4.12) −C​t​ωy≤(−1​∂∂¯​φt)|Xy=(−1​∂∂¯​(φt−φt¯))|Xy≤C​t​ωy.-Ct\omega_{y}\leq(\sqrt{-1}\partial\overline{\partial}\varphi_{t})|_{X_{y}}=(\sqrt{-1}\partial\overline{\partial}(\varphi_{t}-\underline{\varphi_{t}}))|_{X_{y}}\leq Ct\omega_{y}.

The form −1​∂∂¯​η∧(ω0+−1​∂∂¯​φt¯)k\sqrt{-1}\partial\overline{\partial}\eta\wedge(\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}})^{k} is the pullback of a form from YY, and so we can use (4.12) to estimate

|−1​∂∂¯​η∧(ω0+−1​∂∂¯​φt¯)k∧(t​ωX)n−k−i∧(−1​∂∂¯​(φt−φt¯))i−1ωXn|≤C​tn−m,\left|\frac{\sqrt{-1}\partial\overline{\partial}\eta\wedge(\omega_{0}+\sqrt{-1}\partial\overline{\partial}\underline{\varphi_{t}})^{k}\wedge(t\omega_{X})^{n-k-i}\wedge(\sqrt{-1}\partial\overline{\partial}(\varphi_{t}-\underline{\varphi_{t}}))^{i-1}}{\omega_{X}^{n}}\right|\leq Ct^{n-m},

and so the term (4.11) goes to zero. This proves our claim.

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